this is my third time asking this and no answer, i need to get this done today. i will give brainliest.i'm having a bit of trouble with thisA rectangular lawn has an area of 2,030 square meters. Its perimeter is 198 meters. What are the dimensions of the lawn? Show work

Answer:   29 by 70 metersStep-by-step explanation:You need to know how area and perimeter relate to the dimensions of the lawn.The area formula is ...   A = LW . . . . . . . the product of length and widthThe perimeter formula is ...   P = 2(L+W) . . . . twice the sum of length and widthThe latter tells you the sum of length and width will be ...   P/2 = L + W = (198 m)/2 = 99 m__It usually works well to assume that the dimensions are integers, then look for the factors of the area figure that give the right perimeter.   2030 = 2·5·7·29   = 2×1015 = 5×406 = 7×290 = 10×203 = 14×145 = 29×70 = 35×58Of these factor pairs, the one that has a sum of 99 is (29, 70).The dimensions of the lawn are 29 m by 70 m._____You can also solve this graphically or algebraically. The graphical solution finds the points of intersection between LW=2030 and L+W=99, or the equivalent. Attached is a graph of the problem.The algebraic solution can use substitution:   L = 99-W   2030 = (99 -W)(W)   W² -99W +2030 = 0 . . . . subtract the right side and put in standard form   W = (99±√(99² -4·2030))/2 . . . . . . use the quadratic formula   W = (99 +√1681)/2 = (99 ±41)/2 = {29, 70}It doesn't matter which dimension you call the width.The lawn is 29 m by 70 m._____The quadratic formula tells you the solution to ...   [tex]ax^2+bx+c=0[/tex]is given by ...   [tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]Here, we have a=1, b=-99, c=2030. Of course (-99)² = 99², and 4(1)(2030) = 4·2030, so we have simplified the solution a little bit when writing it above.